SOLUTION: The length of a rectangle is 4 feet less than twice the width. The perimeter is 52 feet. Find the length and width.

Question 1162251: The length of a rectangle is 4 feet less than twice the width. The perimeter is 52 feet. Find the length and width.
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 4 feet less than twice the width. The perimeter is 52 feet. Find the length and width.
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L = 2W - 4
P = 2W + 2L = 52
Answer by ikleyn(52786) (Show Source): You can put this solution on YOUR website!
.

It means that 6 times the width is 8 feet shorter than 52 feet.

In other terms, 6 times the width is 60 feet long;

hence, the width is 10 feet and the length is 2*10-4 = 16 feet.

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Solved (mentally).

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