SOLUTION: The area of a trapezoid is 3440 square inches, and the lengths of its parallel sides are in a 3:5 ratio. A diagonal divides the trapezoid into two triangles. What are their areas?

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Question 1158583: The area of a trapezoid is 3440 square inches, and the lengths of its parallel sides are in a 3:5 ratio. A diagonal divides the trapezoid into two triangles. What are their areas?
Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
.
=9/25


= 34/25

=
Area of (triangle) ACD =25*3440/34 =2529 cm^2








Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.

Triangles ADC and ABC have COMMON altitude; therefore, the ratio of their areas is the same as the ratio of their bases |AD| : |BC| = .


Since the sum od the areas of these triangles is 3440 square inches, 


    the area of the triangle ADC is   =  = 1290 sq. inches;


    the area of the triangle ABC is   =  = 2150 sq. inches.

Solved.

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What is written in the post by @mananth,  is   W R O N G   from the first line to the end.




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