SOLUTION: To the nearest tenth of a degree, calculate the angles of the triangle with vertices (0, 0), (6, 3), and (1, 8).

Question 1154772: To the nearest tenth of a degree, calculate the angles of the triangle with vertices (0, 0), (6, 3), and (1, 8).
Answer by VFBundy(438) (Show Source): You can put this solution on YOUR website!

Use the Law of Cosines:

C² = A² + B² - 2AB(cos c)

=

=

=

=

=

=

=

=

c = 1.2491

Now, use the Law of Sines:

=

=

Cross-multiply:

=

=

=

b = 1.0393

So, we know b = 1.0393 radians. This is 59.6 degrees. We also know c = 1.2491 radians. This is 71.6 degrees.

Subtracting both these numbers from 180 degrees, this means a = 48.8 degrees.

In summary:

a = 48.8 degrees
b = 59.6 degrees
c = 71.6 degrees
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