SOLUTION: Find the equation of the locus of a point which moves so that its distance from the point C (3, 4) is always equal to 5.
a. x2 + y2 + 6x - 8y = 0
b. x2 + y2 + 6x + 8y = 0
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Question 1146433: Find the equation of the locus of a point which moves so that its distance from the point C (3, 4) is always equal to 5.
a. x2 + y2 + 6x - 8y = 0
b. x2 + y2 + 6x + 8y = 0
c. x2 + y2 - 6x - 8y = 0
d. x2 + y2 - 6x + 8y = 0
Found 2 solutions by richwmiller, KMST:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
duplicate
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
it has to be the equation of a circle.
For a circle of radius K=any positive number,
centered at (3,4), the equation would be
, which "simplifies" to
The answer is obviously
c. x2 + y2 - 6x - 8y = 0,
unless they were tricking you,
and there is no positive number K such that is .
( is zero).
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