SOLUTION: The perimeter of a rectangular field is 44m and its area is 105m^2. Find the dimension of the field.

Question 1137206: The perimeter of a rectangular field is 44m and its area is 105m^2. Find the dimension of the field.
Found 2 solutions by josmiceli, greenestamps:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = perimeter
Let = area
Let = length
Let = width
----------------------------
m

(1)
and
m2
(2)
----------------------------
(1)
(2)
(2)
(2)
(2)
(2)
(2) ( +square root of 16 gives the wrong answer )
(2)
and
(1)
(1)
--------------------------
The dimensions are 7m by 15m
check:

OK

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

The semiperimeter (length plus width) is 44/2 = 22; the area (length times width) is 105.

Mentally, find two numbers whose product is 105 and whose sum is 22:
105*1 no...
35*3 no...
21*5 no...
15*7 AHA!

ANSWER: The field is 15m by 7m
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