SOLUTION: A baseball is thrown into the air from an initial height of 6 feet with an upward velocity of 38 ft/sec. the function h=-16t^2+37t+6 gives the height after t seconds. How long does

Question 1131294: A baseball is thrown into the air from an initial height of 6 feet with an upward velocity of 38 ft/sec. the function h=-16t^2+37t+6 gives the height after t seconds. How long does it take for the ball to reach maximum height
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
h=-16t^2+37t+6
t for maximum height is the vertex or -b/2a or -37/-32 or 1.15625 seconds ANSWER
f(1.15625)=-21.39+42.78+6=27.39 feet

Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
Let me notice that the input numbers in your post are not consistent . . .

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