SOLUTION: Find the dimensions of the box described.
The length is twice as long as the width. The height is 4 inches greater than the width. The volume is 48 cubic inches.
Algebra.Com
Question 1127660: Find the dimensions of the box described.
The length is twice as long as the width. The height is 4 inches greater than the width. The volume is 48 cubic inches.
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
Using L=2W and H=W+4:
The only real valued solution is W=2
W=2 —> L=4
W=2 —> H=6
——
Ans: W=2in, L=4in, H=6in
——
Check: 2*4*6 = 48
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