SOLUTION: In the trapezoid CB=12, AB=30, CD=8 and angle B=30. What is the area? I should not use trigonometry to solve this problem.

Question 1120270: In the trapezoid CB=12, AB=30, CD=8 and angle B=30. What is the area? I should not use trigonometry to solve this problem.
Answer by ikleyn(52792) (Show Source): You can put this solution on YOUR website!
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I will assume that in a trapezoid ABCD the segments AB and DC are parallel bases of the length of 30 and 8 units, respectively..


The lateral side BC is 12 units long.


Since the angle B is of 30 degrees, the height of the trapezoid from the vertex C drawn to the base AB is half of the length BC.


Hence, the altitude of the trapezoid is 6 units long.


Next, the area of a trapezoid (of ANY trapezoid) is the product of the altitude size by half of the sum of its bases.


In your case, the area of the trapezoid is  A =  =  = 6*19 = 114 square units.

Solved.

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