SOLUTION: The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Find the maximum width of the rectangle.
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Question 111678: The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Find the maximum width of the rectangle.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
2L+2w=P
Let width be w.
2*125+2w=300
250+2w=300
250-250+2w=300-250
2w=50
2w/2=50/2
w=25
Check:
2*125+2*25=300 true
Ed
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