SOLUTION: ABCD is a rectangle. BC = 15m and DC = 8 m. BD is the diagonal. F is a point on BD. F is joint to C, such that FC is perpendicular BD. Similarly, E another point on BD and AE jo

Question 1105661: ABCD is a rectangle. BC = 15m and DC = 8 m. BD is the diagonal. F is a point on BD. F is joint to C, such that FC is perpendicular BD. Similarly, E another point on BD and AE jointed such that AE is perpendicular to BD. What is the distance from point E to F. in m.
Answer by Edwin McCravy(20054) (Show Source): You can put this solution on YOUR website!



By applying the Pythagorean theorem to right ΔBCD,
BD = 17

ΔBCD ∽ ΔCFD because they are right triangles with a common
acute angle, so







ΔCFD ≅ ΔAEB is easy to show.

So FD = EB  by cpct



BD = EB + EF + FD



Multiply though by 17







Edwin

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