SOLUTION: A rectangle has an area of 2340 sq.cm.. When the length and width are both increased by 2 cm each, the area is increased by 206 sq. cm. Find the original perimeter.

Question 1101338: A rectangle has an area of 2340 sq.cm.. When the length and width are both increased by 2 cm each, the area is increased by 206 sq. cm. Find the original perimeter.
Found 2 solutions by josgarithmetic, jorel1380:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Rectangle dimensions x and y

-

-
-----either factorize 2340 and look for combinations that work, or substitute and solve a quadratic equation.

discriminant,
-------------one of these will be 'x' and the other is y.

Dimensions: 36 and 65
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let l and w be the width and length of the rectangle, respectively. Then:
lw=2340 and
(l+2)(w+2)=2340+206=2546
So:
l=2340/w
(2340/w +2)(w+2)=2546
2340+4680/w+2w+4=2546
4680/w+2w=202
4680+2w�=202w
2w�-202w+4680=0
w�-101w+2340=0
(w-65)(w-36)=0
w=65 or 36
The width is 36; and the length is 65, making the original perimeter 202cm
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