SOLUTION: Angle A is an inscribed angle of circle P and angle A =90 degree A intercepts circle P at points K and L which must be true about KL A. it is an arc of circle P. B. It is a rad

Question 1084016: Angle A is an inscribed angle of circle P and angle A =90 degree A intercepts circle P at points K and L which must be true about KL
A. it is an arc of circle P.
B. It is a radius of circle P.
C. It is a tangent of circle P.
D. It is a diameter of circle P.
Answer by Edwin McCravy(20055) (Show Source): You can put this solution on YOUR website!



An inscribed angle is measured by one-half its intercepted
arc.

Angle A = 90� which is one-half its intercepted 
arc KQL. So arc KQL = 180� which is a semicircle, since
a whole circle is 360�, twice 180�.

Therefore KL is a ________?

If you need for me to tell you, say so in the thank-you note
form below and I'll get back to you by email.

Edwin

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