SOLUTION: The height of a door is 2.3 feet longer than its​ width, and its front area is 1626.8 square feet. Find the width and height of the door.

Algebra.Com
Question 1077918: The height of a door is 2.3 feet longer than its​ width, and its front area is 1626.8 square feet. Find the width and height of the door.
Answer by rapture(86)   (Show Source): You can put this solution on YOUR website!


The height here is the length of the door.

Let h = height = length of door

h = (x + 2.3)

Let w = width

w = x

A = hw


The area is given to be 1626.8 square feet

Substitute the above values into A = hw.


1626.8 = (x + 2.3)x


1626.8 = x^2 + 2.3x


Solve for x.


Can you take it from here?


RELATED QUESTIONS

The height of a door is 1.3 feet longer than its​ width, and its front area is... (answered by MathLover1,ikleyn)
The height of a door is 1.6 feet longer than its width and its front area(neglecting... (answered by jorel1380)
The area of a rectangular door is 20.77 square feet. The width of the door is 3.6 feet... (answered by macston)
The length of a rectangular garden is 6 feet longer than its width. If the area of the... (answered by Alan3354)
The area of a rectangular wall of a barn is 280 square feet. Its length is 8 feet longer (answered by harpazo)
The area of a rectangular wall of a barn is 198 square feet. Its length is 4 feet longer (answered by checkley71)
the area of a rectangle is 56 square feet. its lenght is 10 feet longer than the width.... (answered by praseenakos@yahoo.com,duckness73)
The length of a rectangular sign is 4 feet longer than the width. If the sign's area is... (answered by rothauserc)
he area of a rectangular wall of a barn is 280 square feet. Its length is 8 feet... (answered by josgarithmetic)