SOLUTION: The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rectangle?

Question 107727: The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rectangle?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rectangle?
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Let the width be "w"
Then the length is "4w+1"
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Area = width*length
65 = w(4w+1)
65 = 4w^2+w
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Rearrange:
4w^2+w-65 = 0
w = [-1 +- sqrt(1 - 4*4*-65)]/8
w = [-1 +- sqrt(1041)]/
w = [-1 +- 32.2645...]/8
w = 3.908...cm (width of the rectangle)
4w+1 = 16.6322...cm (length of the rectangle)
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Cheers,
Stan H.

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