# SOLUTION: A bus leaves a station at 1 pm traveling west at an average rate of 44 miles per hour. One hour later a second bus leaves the same station, traveling east at an rate of 48 miles pe

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 Question 107377: A bus leaves a station at 1 pm traveling west at an average rate of 44 miles per hour. One hour later a second bus leaves the same station, traveling east at an rate of 48 miles per hour. At what time will the two buses be 274 miles apart?Answer by ankor@dixie-net.com(15622)   (Show Source): You can put this solution on YOUR website!A bus leaves a station at 1 pm traveling west at an average rate of 44 miles per hour. One hour later a second bus leaves the same station, traveling east at an rate of 48 miles per hour. At what time will the two buses be 274 miles apart? : Let t = travel time of the westbound bus when they are 274 mi apart Then (t-1) = travel time of the eastbound bus when they are 274 mi apart : Write a distance equation: Distance = speed * time : West bus dist + East bus dist = 274 mi 44t + 48(t-1) = 274 44t + 48t - 48 = 274 92t = 274 + 48 92t = 322 t = 322/92 t = 3.5 hrs is the travel time of the west bound bus Then we know: 2.5 hrs is the travel time of the east bound bus : Find the time: 1:00 + 3:30 = 4:30 PM, time they will be 274 mi apart : Check solution by finding the sum of the distances: 44(3.5) + 48(2.5) = 154 + 120 = 274 mi as given : : Did this make sense to you? Any questions?