SOLUTION: Find the dimensions of a rectangle whose length is 6 inches greater than its width. The area is 72 square inches. Show your work and explain the steps you used to find the solution

Question 1070528: Find the dimensions of a rectangle whose length is 6 inches greater than its width. The area is 72 square inches. Show your work and explain the steps you used to find the solution in order to receive full credit.
Answer by DENNIS DON(8) (Show Source): You can put this solution on YOUR website!
let L and W be the length and width of the rectangle
L=W+6
Area=L*W
= (W+6)*W
= W�+6W
also;
area=72
then;
W�+6W=72
W�+6W-72=0
(W-6)(W+12)=0
W=6 or W=-12
BUT the dimension can't be negative
then;
W=6, and
L=6+6
=12
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