SOLUTION: How much water should be mixed to a 500 mL of 30% solution of alcohol to have a resulting concentration of 20%?

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Question 1062706: How much water should be mixed to a 500 mL of 30% solution of alcohol to have a resulting concentration of 20%?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
v, how much water



Answer by ikleyn(52779)   (Show Source): You can put this solution on YOUR website!
.
How much water should be mixed to a 500 mL of 30% solution of alcohol to have a resulting concentration of 20%?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Your equation is

 = 0.2,

where W is unknown amount (volume) of water in mL.

The equation is equivalent to

0.3*500 = 0.2*(500 + W).


Simplify and solve for W.

There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".



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