SOLUTION: Write the equation of the line L if L has y-intercept (0,2) and is perpendicular to the line with equation 2x-3y=6.

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Question 105899: Write the equation of the line L if L has y-intercept (0,2) and is perpendicular to the line with equation 2x-3y=6.
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
Y=mx+b
m=slope
2x-3y=6
-3y=-2x+6 add -2x to each side
y=(2/3)x-2 divide each side by -3.
m=2/3
For a line perpendicular to the above line the formula for slope is m= -1/m[1]
m=-3/2 the point is (0,2)
Ed
Solved by pluggable solver: FIND a line by slope and one point

What we know about the line whose equation we are trying to find out:

  • it goes through point (0, 2)

  • it has a slope of -1.5



First, let's draw a diagram of the coordinate system with point (0, 2) plotted with a little blue dot:



Write this down: the formula for the equation, given point and intercept a, is

(see a paragraph below explaining why this formula is correct)

Given that a=-1.5, and , we have the equation of the line:



Explanation: Why did we use formula ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (, ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (, ): Here, we know a, , and , and do not know b. It is easy to find out: . So, then, the equation of the line is: .

Here's the graph:




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