SOLUTION: Mr Flores has a circular fountain with a radius of 5feet. He plans on installing a brick path around the fountain. (Shows small circle 5ft radius then outer circle 9 ft with line

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Question 1052752: Mr Flores has a circular fountain with a radius of 5feet. He plans on installing a brick path around the fountain. (Shows small circle 5ft radius then outer circle 9 ft with line from center dot to outer line of second circle. ) If each brick covers 2 square feet, how many bricks will he need?
Help please
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Area of the brick path: pi%2A%289-5%29%5E2
pi%2A16
16%2Api, square feet.


How many bricks: 16%2Api%2A%281%2F2%29%28sqrFeet%29%28bricks%2FsqrFeet%29=8pi.

This needs to be (most likely) a Natural Number, 25 being the best choice.
If some breaks needed to be cut to fill missing spots, then you might go up to maybe 25%261%2F8.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
Mr Flores has a circular fountain with a radius of 5feet. He plans on installing a brick path around the fountain. (Shows small circle 5ft radius then outer circle 9 ft with line from center dot to outer line of second circle. ) If each brick covers 2 square feet, how many bricks will he need?
Help please
highlight_green%28matrix%281%2C5%2C+87.9645943%2C+rounded%2C+to%2C+88%2C+bricks%29%29

Ignore JOSG/JOGS

Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.
Area of the brick path A = pi%2AR%5E2-pi%5Er%5E2 = pi%2A%289%5E2-5%5E2%29 = pi%2A%2881-25%29 = 3.14%2A56 = 175.84 sq.ft (approximately).

The number of bricks = 175%2F84%2F2 =~ 88.

Answer. 88 bricks.