SOLUTION: Sec^2 theta +Cos^2 Theta >1 for any acute angle theta

SOLUTION: Sec^2 theta +Cos^2 Theta >1 for any acute angle theta

Algebra.Com

Question 1049868: Sec^2 theta +Cos^2 Theta >1 for any acute angle theta
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Is that a question?
Or are you informing us?
RELATED QUESTIONS
if theta is an acute angle and cos theta = 1/2, find sin theta and tan... (answered by lwsshak3)

Prove that tan^2 theta/ (sec^2 theta-1)^2 =1+cos theta/1- cos theta (answered by mananth)

Prove that sec theta -1/ sec theta +1=(sin theta/1+cos... (answered by Alan3354)

Prove that Tan^ 2 theta / ( Sec theta -1 )^2 = 1+ cos theta/ 1- cos... (answered by Alan3354)

Prove the identity: sin^2 theta/1-cos theta = (sec theta + 1)/sec theta (answered by stanbon)

{{{sec^2(theta) - cos^2(theta) *sec^2(theta)}}} (answered by mananth,greenestamps)

simplify the following... (answered by Alan3354)

Verify Cos(theta) / (1+cos(theta)) + cos(theta)/(1-cos(theta)) = 2 cot(theta)... (answered by Edwin McCravy)

if theta is an acute angle and sin theta is 1/2, the value of cos (pie/2+theta) is (answered by Alan3354)