SOLUTION: The length of a rectangle is 8 cm more than its width. If the length is decreased by 9 and the width is tripled, the area is increased by 50%. What was the area of the original tri
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Question 1048957: The length of a rectangle is 8 cm more than its width. If the length is decreased by 9 and the width is tripled, the area is increased by 50%. What was the area of the original triangle?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
What was the area of the original - did you mean to say, RECTANGLE?
, original area
Changed rectangle, , the 50% area increase.
-
-------steps might be not the best path, but this equation is still useful.
Re-substitute for A.
------substituted for w;
-
Maybe the constant term is better factorable.
-----or maybe this not too useful yet.
-
-----general solution of quadratic formula;
---------97 is a prime number.
Approx, , and
If taking the PLUS form of L,
Original area, 820
If taking the MINUS form of L,
Original area, 68
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
The length of a rectangle is 8 cm more than its width. If the length is decreased by 9 and the width is tripled,
the area is increased by 50%. What was the area of the original rectangle?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
, original area
Changed rectangle, , the 50% area increase.
-
---> ---> L = = 18 cm.
Then W = L - 8 = 18-8 = 10 cm. Hence, the area was 10*18 = 180 .
Answer. The dimensions were 10 cm and 18 cm. The area was 180 .
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