SOLUTION: The length of a rectangle is 3 m more than twice the width and the area of the rectangle is 35 m2 . Find the length and width of the rectangle.

Algebra.Com
Question 1043016: The length of a rectangle is
3 m
more than twice the width and the area of the rectangle is
35 m2
. Find the length and width of the rectangle.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The length of a rectangle is
3 m
more than twice the width and the area of the rectangle is
35 m2
--------
L = 2W + 3
L*W = 35
---
sub for L
W*(2W+3) = 35
2W^2 + 3W - 35 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=289 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 3.5, -5. Here's your graph:

============
W = 3.5 meters
L = 10
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