SOLUTION: a rectangle house lot has an area of 1050 square meters. Its length exceeds its width by 5 meters. What is the dimension of the lot? solve as quadratic equation.

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Question 1039: a rectangle house lot has an area of 1050 square meters. Its length exceeds its width by 5 meters. What is the dimension of the lot? solve as quadratic equation.
Answer by usyim88hk(157) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the width and set up an equation:
:
x(x+5) = 1050
:
Then multiply x with (x+5)
:
x^2+5x = 1050
:
then subtract 1050 from both sides
:
x^2+5x-1050 = 0
Now use the quadratic formula to slove
x=%28%28-5%2B-sqrt%28%28-5%29%5E2-4%281%29%28-1050%29%29%29%2F%282%281%29%29%29
x=%28%28-5%2B-sqrt%2825%2B4200%29%29%2F2%29
x=%28-5%2B-65%2F2%29
x = -70/2 or 60/2
x = -35 or 30
Since length can not be negative number, -35 will not be the answer, and 30 is the real answer.
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Dimension of the hopuse lot is 30 x 35