SOLUTION: the perimeter of a piece of cardboard is 34 inches. squares measuring 2 inches on a side are cut from each corner so that when sides are folded up, the diagonal of the resulting bo
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Question 1018209: the perimeter of a piece of cardboard is 34 inches. squares measuring 2 inches on a side are cut from each corner so that when sides are folded up, the diagonal of the resulting box has length 7 inches. what are the original dimensions of the cardboard?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Account for perimeter of the uncut rectangle:
when that equation simplified.
The dimensional measurements for the base surface after the four cut squares removed and flaps folded become and .
The given diagonal value, through the THREE dimensions follows Pythagorean Theorem formula: , since the diagonal was given as 7.
The equations outlined in red color form a system to solve.
The 3-d diagonal equation should be simplified first...
, and go from there...
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