# SOLUTION: Solve. The length of a rectangular room is 4 feet longer than twice the width. If the room's perimeter is 140 feet, what are the room's dimensions?

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 Question 101564: Solve. The length of a rectangular room is 4 feet longer than twice the width. If the room's perimeter is 140 feet, what are the room's dimensions? Answer by doukungfoo(195)   (Show Source): You can put this solution on YOUR website!The perimeter of a rectangle is equal to the sum of all its sides. A rectangle has two sides that represent its length and two sides that represent its width. So with this knowledge about a rectangle we can write a formula: 2(Length) + 2(Width) = Perimeter Thats 2 times the length plus 2 times the widthe equals perimeter. Now we are told that the length of a rectangular room is 4 ft longer than twice its width. Lets set width equal to x. Width = x Now define the length in terms of x Length = 2x + 4 We are given the perimeter is 140 feet. Now we can plug all this information into our formula and solve for x: 2(Length) + 2(Width) = Perimeter 2(2x+4) + 2(x) = 140 4x + 8 + 2x = 140 6x + 8 = 140 6x = 132 x = 22 Answer: the width is 22 ft Now find the length Length = 2x + 4 Length = 2(22) + 4 Length = 44 + 4 Length = 48 Answer: the length is 48 ft Check answers: 2(Length) + 2(Width) = Perimeter 2(48) + 2(22) = 140 96 + 44 =140 140 = 140