SOLUTION: The length of a rectangle is 9 inches less than twice its width. If the border is 1 inch wide, and its area is 52 square inches, what are the dimensions of the picture alone?
Algebra.Com
Question 1014552: The length of a rectangle is 9 inches less than twice its width. If the border is 1 inch wide, and its area is 52 square inches, what are the dimensions of the picture alone?
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
You need to improve the description. Not clear as written in your request. Is the border INSIDE or OUTSIDE?
RELATED QUESTIONS
The area of a rectangle is 91 square inches. Its length is 1 inch less than twice its... (answered by ewatrrr)
The length of a picture without its border is 7 inches less than twice its width. If the (answered by ankor@dixie-net.com)
if The length of a rectangle is 1 inch less than twice its width, and its perimeter is 40 (answered by Fombitz)
A rectangle is twice as long as it is wide. If its length and width are each reduced by 1 (answered by amoresroy)
The width of a rectangle is 2 inches less than its length. Find the length and width if... (answered by algebrahouse.com)
The area of a rectangle is 91 square inches. It's length is 1 inch les than twice its... (answered by JBarnum,Alan3354)
the length of a rectangle is 1 inch less than twice that of its width. If the perimeter... (answered by fractalier)
The length of a rectangle is 1 inch more than four times its width. The perimeter is 52... (answered by Nada)
The width of Jennica’s small painting is 3 inches less than its length. A 1-inch border (answered by ankor@dixie-net.com,greenestamps)