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A regular polygon's interior angle is 8 times as large as its exterior angle
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Hello,
your posting is not complete! A question is absent.
Therefore, I will add the question instead of you, as I understand it.
The question is: Find the number of sides of the polygon.
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First let us find the interior angle .
According to the condition,
+ = 180°.
Hence, + = 180°*8, or = 180°*8, or = = 20°*8 = 160°.
Now find n, the number of sides, from the equation
= 160, or
(n-2)*180 = n*160 -----> (n-2)*9 = n*8, -----> 9n - 18 = 8n -----> 9n - 8n = 18 -----> n = 18.
Answer. The number of sides of the regular polygon is 18.
A regular polygon's interior angle is 8 times as large as its exterior angle
If number of sides are required, then read on!
Let number of sides be n
A regular polygon has equal angles and sides
Therefore, one of its exterior angles is: (sum of exterior angles of a polygon is ), and one of its interior angles is:
We then get:
180n – 360 = 2,880 ------ Multiplying by LCD, n
180n = 2,880 + 360
180n = 3,240
n, or number of sides = , or