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A pilot flew a jet from City A to City B, a distance of 2200 mi. On the return trip, the average speed was 20% faster
than the outbound speed. The round-trip took 8 h 20 min. What was the speed from City A to City B?
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Let u be the speed from City A to City B, in mph.
Then the speed on the return trip was 1.2u.
Time spent for the trip from A to B was hours.
Time spent for the trip from B to A was hours.
An equation is
+ = , or
+ = .
Simplify and solve it for u.
As the first step, multiply both sides by 3*1.2*u.