SOLUTION: A triangle has a perimeter of 165 cm. The first side is 65 cm less than twice the second side. The third side is 10 cm less the second side. Write and solve an equation to find the

Question 1007253: A triangle has a perimeter of 165 cm. The first side is 65 cm less than twice the second side. The third side is 10 cm less the second side. Write and solve an equation to find the length of each side of the triangle.
Found 2 solutions by tiffany222, It is costly:
Answer by tiffany222(56) (Show Source): You can put this solution on YOUR website!
Let x be the first side
Let y be the second side
Let z be the third side
x = 2y - 65
z = y - 10
x + y + z = 165
(2y -65) + y + (y-10) = 165
4y -75 = 165
4y = 240
y = 60
x = 2y - 65 = 2(60) - 65 = 55
z = y - 10 = 60 - 10 = 50
Equation: (2y -65) + y + (y-10) = 165
Final Answer:
First side = 55 cm
Second side = 60 cm
Third Side = 50 cm

Answer by It is costly(175) (Show Source): You can put this solution on YOUR website!

p=165
1st. side =2x-65 =2[60]-65 = 120-65= [55cm.]
2nd. side =x = [60cm.]
3rd. side =x-10 =60-10= [50cm.]
p=1st.side +2nd.side +3rd side
165=2x-65 +x + x-10
165=4x -75
165+75=4x
240=4x
240/4=4x/4
60=x
60cm=x

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