SOLUTION: The consecutive sides of a rectangle are (x+11) units and (3x+8) units, and the perimeter is 70 units. Find the measure of its diagonal.

Question 1003134: The consecutive sides of a rectangle are (x+11) units and (3x+8) units, and the perimeter is 70 units. Find the measure of its diagonal.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 2(l+w)
(3x+8) & (x+11)
Perimeter = 2((x+11)+(3x+8))
2(x+11+3x+8) = 70
2(4x+19)=70
/2
4x+19=35
4x= 35-19
4x= 16
x=4
(x+11) = 4+11=15
3x+8 => 3*4+8=> 20
Using Pythagoras theorem
Diag^2 = 15^2+20^2
= 225+400
= 625
diagonal = sqrt(625)
= 25
Diagonal = 25 units

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