SOLUTION: Find the center and radius of the circle with the given equation. x^2+y^2-8y=9

Question 1002386: Find the center and radius of the circle with the given equation.
x^2+y^2-8y=9
Found 2 solutions by fractalier, Cromlix:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
We have to complete the square by adding 16 to both sides...from
x^2+y^2-8y=9
x^2+y^2-8y+16 = 25
x^2 + (y-4)^2 = 5^2
so that the center is at
(0,4) with a radius of 5.
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
x^2+y^2-8y=9
x^2 + y^2 - 8y - 9 = 0
Centre is obtained by halving the integers before
the x and y components and making them negative
of the equation
Centre (0, 4)
...........
Radius = sqrt x coord of centre squared +
y coord of centre squared - the integer at
the end of the equation (-9)
Radius = sqrt of 0^2 + 4^2 + 9
= sqrt25
= 5
Hope this helps :-)
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