Lesson Angle bisector drawn to the hypotenuse of a right triangle

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Angle bisector drawn to the hypotenuse of a right triangle


This lesson focuses on angles in a right triangle.

Problem
In a right triangle, the angle bisector, the altitude and the median are drawn from the right angle vertex to the hypotenuse.
Prove that the angle bisector of the right angle bisects the angle between the altitude and the median too.

Solution
Figure 1 shows the right triangle ABC. The angle ACB is the right             
angle. The altitude AD (red line), the angle bisector AE (blue line)
and the median AF (green line) are drawn from the right angle
vertex (point C) to the hypotenuse AB.
We need to prove that the angle bisector CE of the right angle ACB
bisects the angle DCF too.

The proof is very simple (Figure 2).
Let alpha be the angle ABC and beta be the angle BAC.
In the right triangle ABC the angle BAC is complement to the
angle ABC, therefore beta = 90° - alpha (see the lesson Angles basics
under the topic Angles, complementary, supplementary angles
of the section Geometry in this site).


Figure 1. The angle bisector, the altitude      
          and the median of a right triangle


Figure 2. To the solution of the Problem

In the right triangle ADC the angle ACD is complement to the angle CAD. Therefore, the angle measure of the angle ACD is equal to 90° - beta = 90° - (90° - alpha) = alpha.
So, the angle ACD is congruent to the angle ABC. This is why in Figure 2 we denoted the angle ACD by the same symbol alpha as the angle ABC.

From the other side, the median in a right triangle divides it in two isosceles triangles. This fact was proved in the lesson Median in a right triangle drawn to its hypotenuse
under the current topic Geometry of the section Word problems in this site.
In our case, this means that the triangle BFC is the isosceles triangle. Hence, the angles FBC and FCB are congruent and both have the same angle measure alpha.

The rest of the proof is straightforward.
Since the segment CE is the angle bisector of the right angle ACB, the angles ACE and BCE have the angle measure 45° each.
The angle DCE has the angle measure 45° - alpha. The angle ECF has the angle measure 45° - alpha too.
Since the angles DCE and ECF have the same angle measures, they are congruent. Hence, the segment CE bisects the angle DCF. The proof is completed.

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