SOLUTION: Stacey is selling tickets to the school play. The tickets are $8 for adults and $3 for children. She sells twice as many adult tickets as children's tickets and brings in a total o
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Question 952378: Stacey is selling tickets to the school play. The tickets are $8 for adults and $3 for children. She sells twice as many adult tickets as children's tickets and brings in a total of $380. How many of each kind of ticket did she sell?
Found 2 solutions by macston, lwsshak3:
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
A=adult tickets=2C; C=child tickets
$8A+$3C=$380 Substitute for A
$8(2C)+$3C=$380
$16C+$3C=$380
$19C=$380 Divide each side by $19
C=20 ANSWER 1: She sold 20 Child tickets.
A=2C=2(20)=40 ANSWER 2: She sold 40 Adult tickets.
CHECK:
$8A+$3C=$380
$8(40)+$3(20)=$380
$320+$60=$380
$380=$380
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Stacey is selling tickets to the school play. The tickets are $8 for adults and $3 for children. She sells twice as many adult tickets as children's tickets and brings in a total of $380. How many of each kind of ticket did she sell?
***
let x=number of children's tickets sold
2x=number of adult tickets sold
3x+8*2x=380
19x=380
x=380/19=20
2x=40
number of children's tickets sold=20
number of adult tickets sold=40
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