SOLUTION: Jack and Jill are trying to figure out how much each movie ticket costs. Jack knows that the adult tickets are 2 times plus 1 more than the children tickets. Jill knows that they s
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Question 949090: Jack and Jill are trying to figure out how much each movie ticket costs. Jack knows that the adult tickets are 2 times plus 1 more than the children tickets. Jill knows that they sold 45 adult tickets and 70 children tickets and made $525. How much is each ticket?
I need to solve this with the systems of substitution. I need to know how to write 2 equations out so I can solve for x and y.
Found 2 solutions by stanbon, josgarithmetic:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Jack and Jill are trying to figure out how much each movie ticket costs. Jack knows that the adult tickets are 2 times plus 1 more than the children tickets. Jill knows that they sold 45 adult tickets and 70 children tickets and made $525. How much is each ticket?
I need to solve this with the systems of substitution. I need to know how to write 2 equations out so I can solve for x and y.
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a = 2c+1
45a + 70c = 525
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Substitute for "a" and solve for "c"::
45(2c+1) + 70c = 525
90c+45 + 70c = 525
160c = 480
c = 3 dollars (price of one child ticket)
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Solve for "a"
a = 2c + 1
a = 6+1
a = 7 dollars (price of one adult ticket)
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Note: You could use x and y but your problem lends
itself better to using "a" and "c".
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Cheers,
Stan H.
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
x, adult price
c, child price
-
x=2c+1
-
45 adult tickets, and 70 children tickets, revenue $525:
substitute for x.
Continue from that.
The TWO EQUATIONS you would start with is this system:
You could use y instead of c if you want. Just be clear about saying what each variable means.
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