SOLUTION: A wallet contains $5 bills and $10 bills. There are 15 bills in the wallet with a total value of $120. Determine the number of $5bills and the number of $10 bills in the wallet.

Question 94746This question is from textbook
: A wallet contains $5 bills and $10 bills. There are 15 bills in the wallet with a total value of $120. Determine the number of $5bills and the number of $10 bills in the wallet. This question is from textbook

Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=number of $5 bills
Then 15-x=number of $10 bills
Now we are told that: (dollars are understood)
5x+10(15-x)=120 get rid of parens
5x+150-10x=120 subtract 150 from both sides
5x+150-150-10x=120-150 collect like terms
-5x=-30 divide both sides by -5
x=6----------------number of $5 bills
15-6=9----------------number of $10 bills
CK
6*5+10*9=120
30+90=120
120=120
Another way:
x=number of $5
y=number of $10
x+y=15--------------------eq1
5x+10y=120-------------------eq2
Notice that if we substituted y=15-x from eq1 into eq2 we end up with the same equation that we initially solved

Hope this helps----------------ptaylor
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