SOLUTION: If it takes 3men 56hours to dig a hole 4mX6mX5m, and two of the men work twice
as fast as the third,find the number of hours that will take the two faster men to dig this hole
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Question 942153: If it takes 3men 56hours to dig a hole 4mX6mX5m, and two of the men work twice
as fast as the third,find the number of hours that will take the two faster men to dig this hole together. ( answer is 70hours - show your solution )
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the rate of working of the slow man
= the rate of working of the two faster men
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Add their rates of working to get rate working together
It takes 70 hrs for the 2 faster men digging together
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check:
OK
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