SOLUTION: A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totaled $487. The second order was for 6 bushes and 2 trees, and totaled

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Question 928480: A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totaled $487. The second order was for 6 bushes and 2 trees, and totaled $232. the bills do not list the per-item price. What were the cost of one bush and 1 tree?
Answer by TimothyLamb(4379)   (Show Source): You can put this solution on YOUR website!
x = cost of bush
y = cost of tree
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13x + 4y = 487
6x + 2y = 232
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put the system of linear equations into standard form
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13x + 4y = 487
6x + 2y = 232
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = cost of bush = 23
y = cost of tree = 47
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Solve and graph linear equations:
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Solve quadratic equations, quadratic formula:
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Solve systems of linear equations up to 6-equations 6-variables:
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