SOLUTION: Zainab sold a phone she bought $25.00 for $35.00. The percent markup is:Select one: 58% 35% 71% 83% 40%

Algebra.Com
Question 922000: Zainab sold a phone she bought $25.00 for $35.00. The percent markup is:Select one:
58%
35%
71%
83%
40%

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Zainab sold a phone she bought $25.00 for $35.00. The percent markup is:Select one:
-----
Quantity markup:: $10.00
Percent markup:: 10/25 = 2/5 = 0.40 = 40%
---------------------
Cheers,
Stan H.
------------
58%
35%
71%
83%
40%

RELATED QUESTIONS

Meal Cost in Hong Kong. The mean cost of a meal for two in a mid-range restaurant in... (answered by math_tutor2020)
Rowena works as a saleslady in SM Department Store. As one of her benefits, she... (answered by Solver92311)
a sport trader bought a basketball jersey for 1,500.00 pesos subject to a 35% trade... (answered by Boreal)
The Stereo Shop sold a radio regularly priced $125.00 for $75.00. The radio was... (answered by ikleyn)
a computer store bought a program for $7.00 and sold it for $10.00 Find the dollar amount (answered by rfer)
brenda sells a phone for 104 dollars. this is 30% markup on the cost she paid for the... (answered by Fombitz)
You are the manager of Motown Hardware. You are currently selling Energy Max batteries... (answered by mananth)
what is the cost of a cel phone which is sold for 250 if the percentage markup is 25% on... (answered by LinnW)
Jessica purchased a prepaid phone card for $35.00. Calls cost cents a minute using this... (answered by josgarithmetic)