Susan is selling tickets to a concert. Seating capacity is 1,500 seats. The rate is $6.00. Susan knows that she can sell 1200 at this price. Every time that she increases the price by $0.75 then her sales decreases by half. write the equation. What is the maximum amount that she can make. Your teacher botched this problem. First of all it is a calculus "minimax" problem, not an algebra problem, since it is not a quadratic. Secondly Susan loses money if she increases the price even by $0.75, for only half the 1500 seats, or 750, are then sold, and that only brings in $5062.50, whereas if she doesn't increase it at all, she takes in $9000. If she increases The price per And the number So her the price by ticket is of ticket sales is intake is 0 $6.00 1500 $9000.00 $0.75 $6.75 750 $5062.50 $1.50 $7.50 325 $2437.50 $2.25 $8.25 162 $1336.50 $3.00 $9.00 81 $ 729.00 $3.75 $9.75 40 $ 390.00 $4.50 $10.50 20 $ 210.00 $5.25 $11.25 10 $ 112.00 $6.00 $12.00 5 $ 60.00 $6.75 $12.75 2 $ 25.50 $7.50 $13.50 1 $ 13.50 $8.25 $14.25 0 $ 0.00 So she makes the most money by not increasing the price at all. Tell your teacher he or she has botched this problem. Here is an attempt at deriving the equation for it: Let x = the number of $0.75 price increases Then the price per ticket is $6.00 + $0.75x >>..Every time that she increases the price by $0.75 then her sales decreases by half..<< So x is also the number of times her sales get cut in half, so the 1500 is multiplied byx times. So the number of sales is 1500 So her total revenue R = (price per ticket)(number of tickets sold) R = (6 + .75x)(1500 So you see it is an exponential equation, not a quadratic, which is probably what your teacher intended it to be. Edwin