SOLUTION: Beth C. Day lived 63 years from 18tu to 18ut. The sum of tu and ut is 11. In what year was Beth C. Day born?
explain why
18tu-18ut=63; to
1800+10t+u-(1800+1
Algebra.Com
Question 844209: Beth C. Day lived 63 years from 18tu to 18ut. The sum of tu and ut is 11. In what year was Beth C. Day born?
explain why
18tu-18ut=63; to
1800+10t+u-(1800+10u+t)=63; - why 10?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
t=2 u=9
1892-1829=63
(1800+10u+t)-(1800+10t+u)=63
why 10?
29 is 10*2+9
92 is 10*9+2
RELATED QUESTIONS
beth C. Day lived 63 years from 18tu to 18ut. The sum of tu and ut is 11. In what year... (answered by ranger)
Beth C. Day lived 63 years from 18tu to 18ut. The sum of tu and ut is 11. In what... (answered by rdhyani)
Beth C. Day lived 63 years from 18tu to 18ut. The sum of tu and ut is 11. In what year... (answered by rdhyani)
Beth C. Day lived 63 years from 18tu to 18ut. The sum of tu and ut is 11. In what year... (answered by richwmiller)
Mike lived for 63 years from 18xy to 18yx. The sum of xy and yx is 11. In what year was (answered by ewatrrr)
Danny was born exactly 4 years before Beth. The product of their age is 96. How old is... (answered by solve_for_x)
The sum of paul and beth’s ages is 67. Eight
years ago paul was twice as old as beth.... (answered by josgarithmetic,ikleyn)
Three sisters, Amy,Beth, and Carly are different ages. Amy is 7 years older than Beth.... (answered by Edwin McCravy)
beth is 11 years old. Sandra is Alice's age older than beth. Alice is half the age beth... (answered by Edwin McCravy,ikleyn)