SOLUTION: John had $ 30,000 to invest. He invested part of this money in bonds paying 12% annual simple interest and the rest of the money in savings account giving 4% annual interest. At th

Algebra.Com
Question 824100: John had $ 30,000 to invest. He invested part of this money in bonds paying 12% annual simple interest and the rest of the money in savings account giving 4% annual interest. At the end of the year, he received $2,400 as extra income. How much money did John place in each investment?
Answer by framos119(1)   (Show Source): You can put this solution on YOUR website!
.4x+.12(30000-x)=2400
.04x+.12(30000)-.12x=2400
.04x+3600-.12x=2400
.12x-.04x+3600=2400
.08x+3600=2400
.08x+3600-3600=2400-3600
8x=1200
(8x/8)=1200/8
X=1500
15000-30000=15000
Total invested at .12=$15,000.00
At .04=$15,000.00
15000*.04=$600.00
15000*.12=$1,800.00
$1,800.00+$600.00=$2,400.00

RELATED QUESTIONS

John had $30,000 to invest. He invested part of this money in bonds paying 12% annual... (answered by mananth)
John had $30,000 to invest. He invested part of this money in bonds paying 12% annual... (answered by josmiceli)
John had $30,000to invest. He invest part of this money in bonds paying 12% annual simple (answered by mananth)
John had $30,000 to invest. He invested part of his money in bond paying 12% annual... (answered by mananth)
John had $30,000. He invested part of his money in bonds paying 12% annual simple... (answered by mananth)
John received an inheritance of $12,000$12,000 that he divided into three parts and... (answered by Boreal)
Merry had $20,000 to invest. She invested part of this money in bonds paying 10% annual... (answered by mananth)
Merry had $20,000 to invest. she invested part of this money in bonds paying 10% annual... (answered by mananth)
Merry had $20,000 to invest. She invested part of this money in bonds paying 10% annual... (answered by mananth)