SOLUTION: an object is dropped from 38 feet below the tip of the pinnacle atop a 362-ft tall building. the height h of the object after t seconds is given by the equation h= -16t^2+324. find

Algebra.Com
Question 823896: an object is dropped from 38 feet below the tip of the pinnacle atop a 362-ft tall building. the height h of the object after t seconds is given by the equation h= -16t^2+324. find how many seconds pass before the object reaches the ground
? seconds pass before the object reaches the ground

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
h= -16t^2+324
---------------
It hits when h = 0

Solve for t.

RELATED QUESTIONS

an object is dropped from 38 feet below the tip of the pinnacle atop a 1482-ft tall... (answered by macston)
an object is dropped from 45 ft below the tip of the pinnacle atop a 945 ft tall... (answered by stanbon)
An object is dropped from 39 feet below the tip of the pinnacle atop one of the... (answered by Alan3354)
The height of an object dropped from a 205 feet tall building is given by h = -16t... (answered by ankor@dixie-net.com)
If an object is dropped from a height of 38 feet, the function h(t)=-16t^2+38 gives the... (answered by Earlsdon)
An object is dropped from the top of a building that is 144 ft high. The function given... (answered by ewatrrr)
An object is dropped off a building that is 144 feet tall. After how many seconds does... (answered by ankor@dixie-net.com)
If an object is dropped from a height of 85 feet, the function h(t)=-16t^2+85 gives the... (answered by Alan3354)
An object dropped from the top of a building passed you on the fifth floor three seconds... (answered by JimboP1977)