SOLUTION: If a vehicle was purchased for $12590.00, which was 20% off the original price, what was the original price?

Question 802: If a vehicle was purchased for $12590.00, which was 20% off the original price, what was the original price?
Found 3 solutions by pushpaharan, JamieL38, longjonsilver:
Answer by pushpaharan(47)   (Show Source): You can put this solution on YOUR website!
let original price = x
then if you reduce the price by 20%, the selling price = x- 20% of x
= x-0.2x
=0.8x = $12590
therfore x = $12590 / 0.8
= $15737.50
;-)
Answer by JamieL38(6)   (Show Source): You can put this solution on YOUR website!
Since the vehicle was purchased for 20% off the original price, the buyer paid 80% of the original price. Let x represent the original price.
Our equation becomes:
80%*x=12590

The vehicle's original price was $16187.50.
Another way to solve this same problem is to subtract 20% of the original price from the original price. The equation would look like this:
x-20%*x=12590
You'll notice it's pretty much the same problem as above when you start working through it. You'll get the same answer.
Answer by longjonsilver(2297)   (Show Source): You can put this solution on YOUR website!
the other answer is so badly wrong, i cannot believe it!
Let x = original price.
The long way (and safest way) is as follows:
Find what 20% of the original is.
Subtract this from the original
that answer is equal to 12590
so...what is 20% of x?...answer is (20/100)*x which is 0.2x
original minus the 20% discount is (x - 0.2x) which is 0.8x and this is equal to the price of $12590
so 0.8x = 12590 --line A
therefore x = 12590/0.8
x = 15737.50
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Quick method.... a % reduction is less than 1 at line A...10% reduction would be 0.9, 25% reduction would be 0.75 etc
An increase would therefore be greater than 1, eg 10% increase is 1.10. 3% increase is 1.03 (NOT 1.3)
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jon
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