SOLUTION: <a href='http://www.mathway.com/answer.aspx?p=calg?p=(2xSMB073+xSMB072-x+1)SMB15SMB10SMB15(2x+3)?p=13?p=?p=?p=?p=?p=0?p=?p=0?p=?p=?p=Divide' target='_blank'><img src='http://www.ma
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Question 731990: 
Answer by Vladdroid(91) (Show Source): You can put this solution on YOUR website!
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