SOLUTION: The owner of a movie theater was counting the money from one day's ticket sales. He knew that a total of 150 tickets were sold. Adult tickets cost $7.50 each and children's tickets
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Question 700285: The owner of a movie theater was counting the money from one day's ticket sales. He knew that a total of 150 tickets were sold. Adult tickets cost $7.50 each and children's tickets cost $4.75 each. If the total receipts for the day were $891.25, how many of each kind of ticket were sold?
Found 2 solutions by mananth, solver91311:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x= number of child tickets
y= number of adult tickets
Total sold
1.00 x + 1.00 y = 150.00 .............1
Total value
4.75 x + 7.50 y = 891.25 .............2
Eliminate y
multiply (1)by -7.50
Multiply (2) by 1.00
-7.50 x -7.50 y = -1125.00
4.75 x + 7.50 y = 891.25
Add the two equations
-2.75 x = -233.75
/ -2.75
x = 85.00
plug value of x in (1)
1.00 x + 1.00 y = 150.00
85.00 + y = 150.00
y = 150.00 -85.00
y = 65.00
y = 65.00
x= 85 number of child tickets
y= 65 number of adult tickets
m.ananth@hotmail.ca
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the number of Adults and 
represent the number of Children. Then
and
Solve the system for and
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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