# SOLUTION: The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet, then what are the length and width? How do I solve this?

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 Question 69860: The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet, then what are the length and width? How do I solve this?Answer by ankor@dixie-net.com(15645)   (Show Source): You can put this solution on YOUR website!Write an equation for each statement/phrase: : "length of a rectangular lot is 50 feet more than the width." L = W + 50 : I assume you know the perimeter equation: "If the perimeter is 500 feet," 2L + 2W = 500 : then what are the length and width? : If we could get the above equation to be a single unknown it would be easy to solve. The 1st equation says that L = (W+50), substitute (W+50) for L in the perimeter equation: 2(W+50) + 2W = 500 : We can simplify this equation by dividing thru by 2, then we have: (W+50) + W = 250; a very simple equation to solve for W : 2W = 250 - 50 2W = 200 W = 200/2 W = 100 ft is the width; : Remember: "length of a rectangular lot is 50 feet more than the width." L = 100 + 50 L = 150 : Check our solutions in the perimeter equation: 2(150) + 2(100) = 500 ; How about this? Comprendez?