You can
put this solution on YOUR website!Joyce makes $6000 more per year than her husband does. Joyce saves 10% of her income for retirement and her husband saves 6%. If altogether they save $5400 per year, then how much does each of them earn per year?
Suppose we let H represent the amount that her husband earns in a year and J represent the
amount that Joyce earns.
The first sentence tells you that J is $6000 more than H. So if we take away $6000 from
J the amount left should be H. In equation form this is:
For later convenience, let's rearrange that by first adding $6000 to both sides and then
subtracting H from both sides to get:
Now let's look at the second part of the information given in the problem.
Joyce saves 10% of her income. That is she saves 10% of J or in decimal form she saves

. Her husband saves 6% of his income or in decimal form he saves

.
Added together, these two amounts of savings totals $5400. In equation form this becomes:
You now have 2 linear equations that can be solved simultaneously:

and
One way to do it is to multiply the entire bottom equation by -10 so that it becomes:
If you add this equation to the first equation, the J and the -J cancel and the resulting
equation becomes:
Calculator time. Divide both sides by -1.6 to get
And since Joyce makes $6000 more than that, you know she makes:
Check by seeing if 10% of Joyce's salary plus 6% of her husband's salary adds up to be $5400.
Hope this helps you to see that problems of this sort require 2 equations to solve, and
that they must be solved as simultaneous linear equations.