SOLUTION: Jerome paid $85 for a calculator. He had no one-dollar bills or coins. How many ways could he have paid if he had no bills more than $20?

Question 698457: Jerome paid $85 for a calculator. He had no one-dollar bills or coins. How many ways could he have paid if he had no bills more than $20?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
There are 25 ways to do this

1 five + 4 twenties = 5 bills total
1 five + 2 tens + 3 twenties = 6 bills total
1 five + 4 tens + 2 twenties = 7 bills total
3 fives + 1 ten + 3 twenties = 7 bills total
1 five + 6 tens + 1 twenty = 8 bills total
3 fives + 3 tens + 2 twenties = 8 bills total
5 fives + 3 twenties = 8 bills total
1 five + 8 tens = 9 bills total
3 fives + 5 tens + 1 twenty = 9 bills total
5 fives + 2 tens + 2 twenties = 9 bills total
3 fives + 7 tens = 10 bills total
5 fives + 4 tens + 1 twenty = 10 bills total
7 fives + 1 ten + 2 twenties = 10 bills total
5 fives + 6 tens = 11 bills total
7 fives + 3 tens + 1 twenty = 11 bills total
9 fives + 2 twenties = 11 bills total
7 fives + 5 tens = 12 bills total
9 fives + 2 tens + 1 twenty = 12 bills total
9 fives + 4 tens = 13 bills total
11 fives + 1 ten + 1 twenty = 13 bills total
11 fives + 3 tens = 14 bills total
13 fives + 1 twenty = 14 bills total
13 fives + 2 tens = 15 bills total
15 fives + 1 ten = 16 bills total
17 fives = 17 bills total

Again, there are 25 ways. Each case has the bills' value adding up to $85.
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