SOLUTION: A total of $7000 is invested: part at 7% and the remainder at 11%. How much is invested at each rate if the annual interest is $760?
Algebra.Com
Question 696497: A total of $7000 is invested: part at 7% and the remainder at 11%. How much is invested at each rate if the annual interest is $760?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
.07x+.11(7000-x)=760
.07x+770-.11x=760
-.04x=760-770
-.04x=-10
x=-10/-.04
x=$250 invested @ 7%.
7000-250=$6750 invested @ 11%.
Proof:
.07*250+.11*6750=760
17.50+742.50=760
760=760
RELATED QUESTIONS
a total of $7000 is invested: part at 9% and the remainder at 11%. How much is invested... (answered by mananth)
A total of
$7000 is invested: part at
7% and the remainder at
12%
.
How much is... (answered by jorel1380)
A total of $7000 is invested: part at 6% and the remainder at 10%. How much is invested... (answered by MathLover1,greenestamps)
a total of $7000 is invested: part at 5% and the remainder at 9%. how much is invested at (answered by FrankM)
A total of $8000 is invested: a part at 7% and remainder at 11%. How much is invested at... (answered by mananth)
A total of $7000 is invested : part at 5% and the remainder at 10%. How much is invested... (answered by Boreal)
A total of $5000 is invested: part at 7% and the remainder at 12%. How much is invested... (answered by srinivas.g)
A total of $7000 is invested:part at 10% and the remainder at 15%. How much is invested... (answered by checkley77)
A total of $8000 is invested, part at 6% and the remainder at 9%. How much is invested at (answered by checkley75)