SOLUTION: Help please. I can't think how to solve this problem. The sum of 12000 USD is invested, part at 12% interest and part at 8% interest. Twice as much money was invested at 8% as at 1

Question 692745: Help please. I can't think how to solve this problem. The sum of 12000 USD is invested, part at 12% interest and part at 8% interest. Twice as much money was invested at 8% as at 12%. How much money was invested at each rate?
Thank you.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = amount invested at 12%
is the amount invested at 8%

$4,000 was invested at 12%
$8,000 was invested at 8%

RELATED QUESTIONS
PLEASE HELP ASAP! Solve the following problem by setting up and solving a system of... (answered by mananth)

The sum of $12,000 is invested, part at 12% interest and part at 8% interest. Twice as... (answered by richwmiller)

Hi, I have a problem that I don't understand how to solve, where there are two different... (answered by ikleyn,greenestamps)

The question is: Tina invested $600, part at 8% interest per year, and the rest at 12%... (answered by jim_thompson5910)

I need help with this problem please: Lane invested $14,000, part at 15% and part at... (answered by checkley75)

Hi, I have been working this problem and I can not get the proper answer. Please help!... (answered by stanbon)

Mike invested $7000 for one year. He invested part of it at 8% and the rest at 12%. At... (answered by jojo14344)

Please hep me solve this word problem. A total of $8000 dollars is invested for one year, (answered by solver91311)

Amy invests a part of $12000 in bonds paying 11% interest. The remainder is in a savings... (answered by ankor@dixie-net.com)